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a b=abcos¦È (ÆâÀÑ)
(-1)¡åcos¦È¡å1
(-ab)¡åabcos¦È¡åab
a b=abcos¦È
(-ab)¡åa b¡åab
a b¡åab
ab¡æa b
a^2b^2¡æ(a b)^2
a=¦¤a
b=¦¤b
(¦¤a)^2(¦¤b)^2¡æ(¦¤a ¦¤b)^2
¦¤a ¦¤b=1/2(¦¤a ¦¤b)+1/2(¦¤a ¦¤b)
¦¤a ¦¤b=1/2(¦¤a ¦¤b)+1/2(¦¤a ¦¤b)+
1/2(¦¤a ¦¤b)-1/2(¦¤a ¦¤b)
¦¤a ¦¤b=1/2(¦¤a ¦¤b)+1/2(¦¤b ¦¤a)+
1/2(¦¤a ¦¤b)-1/2(¦¤b ¦¤a)
¦¤a ¦¤b=1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)]+
1/2[(¦¤a ¦¤b)-(¦¤b ¦¤a)]
¦¤a ¦¤b=1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)+
(¦¤a ¦¤b)-(¦¤b ¦¤a)]
(¦¤a ¦¤b)-(¦¤b ¦¤a)={(a-a')(b-b')-(b-b')(a-a')}
{(a-a')(b-b')-(b-b')(a-a')}=(a b-b a)
(¦¤a ¦¤b)-(¦¤b ¦¤a)=(a b-b a)
¦¤a ¦¤b=1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)+
(¦¤a ¦¤b)-(¦¤b ¦¤a)]
¦¤a ¦¤b=1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)+(a b-b a)]
¦¤a ¦¤b={1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)]+1/2(a b-b a)}
(¦¤a ¦¤b)+(¦¤b ¦¤a)>(¦¤a ¦¤b)-(¦¤b ¦¤a)
(¦¤a ¦¤b)-(¦¤b ¦¤a)=(a b-b a)
(¦¤a ¦¤b)+(¦¤b ¦¤a)>(a b-b a)
{1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)]+1/2[(a b-b a)]}¡æ
[1/2(a b-b a)+1/2(a b-b a)]^2=
[1/4(a b-b a)]^2
{1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)]+1/2[(a b-b a)]}¡æ
[1/4(a b-b a)]^2
¦¤a ¦¤b={1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)]+1/2(a b-b a)}
¦¤a ¦¤b={1/2[(¦¤a ¦¤b)+(¦¤b ¦¤a)]+1/2(a b-b a)¡æ
[1/4(a b-b a)]^2
¦¤a ¦¤b¡æ[1/4(a b-b a)]^2
(¦¤a)^2(¦¤b)^2¡æ(¦¤a ¦¤b)^2
¦¤a ¦¤b¡æ[1/4(a b-b a)]^2
(¦¤a ¦¤b)^2¡æ[1/4(a b-b a)]^4
(¦¤a)^2(¦¤b)^2¡æ(¦¤a ¦¤b)^2¡æ[1/4(a b-b a)]^4
¦¤a ¦¤b¡æ[1/4(a b-b a)]^2
¦¤a ¦¤b¡æ1/2(a b-b a)=1/2(h/2¦Ð)=h/4¦Ð
¦¤a ¦¤b¡æh/4¦Ð
a=p
b=x
¦¤p ¦¤x¡æh/4¦Ð
¦¤p¦¤x¡æh/4¦Ð (ÉÔ³ÎÄêÃÍ)
¦¤p¦¤x=h/4¦Ð (³ÎÄêÃÍ) (ºÇ¾®ÃÍ)