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t=e^x
(¦¤/¦¤x)e^x=e^x
t=e^x
(¦¤/¦¤x)t=e^x=t
¦¤t/¦¤x=e^x=t
v=¦¤x/¦¤t
1/v=¦¤t/¦¤x
¦¤t/¦¤x=e^x=t
1/v=¦¤t/¦¤x=e^x=t
1/v=t
1/v=¦¤t/¦¤x=e^x=t
x=e^t
(¦¤/¦¤t)e^t=e^t
x=e^t
(¦¤/¦¤t)x=e^t=x
¦¤x/¦¤t=e^t=x
v=¦¤x/¦¤t
v=¦¤x/¦¤t=e^t=x
v=x
v=¦¤x/¦¤t=e^t=x
1/v=¦¤t/¦¤x=e^x=t
v=¦¤x/¦¤t=e^t=x
(1/v)v=(¦¤t/¦¤x)(¦¤x/¦¤t)=(e^x)(e^t)=tx=1
(1/v)v=(¦¤t/¦¤x)(¦¤x/¦¤t)=tx=1
tx=1

¦¤x=xn-xn-1
x¦¤x=(x1-x0)+(-x1)+++(xn-1-)+(xn-xn-1)
x¦¤x=-x0+xn
x0=0
xn=C=1
x¦¤x=1
x¦¤x=1
¦¤x=1/x
¦¤¦¤x=¦¤(1/x)
¦¤(1/x)=[1/(x+¦¤x)]-[1/x]
¦¤(1/x)=[x/(x+¦¤x)x]-[(x+¦¤x)/x(x+¦¤x)]
¦¤(1/x)=[x-(x+¦¤x)/x(x+¦¤x)]
¦¤(1/x)=[x-x-¦¤x/x(x+¦¤x)]
¦¤(1/x)=[-¦¤x/x(x+¦¤x)]
¦¤x=1/x
¦¤(1/x)=[-(1/x)/x{x+(1/x)}]
¦¤(1/x)=[-(1/x)/x^2+1]
¦¤(1/x)=[-(1/x)*x/(x^2+1)*x]
¦¤(1/x)=[-1/(x^3+x)]

¦¤¦¤x=¦¤(1/x)
¦¤(1/x)=-1/x
¦¤¦¤x=¦¤(1/x)=-1/x
¦¤(1/x)=-1/x
x=k
¦¤k=¦¤(1/k)=¦¤¦¤(1/k)=¦¤¦¤¦¤(1/k)=¡Ä=[(¦¤)^n](1/k)
1/k=-1/k=1/k=-1/k=¡Ä[(¦¤)^n]¦¤k
1/k=-1/k=1/k=-1/k=¡Ä
k=-k=k=-k=¡Ä
k=tx=1
tx=-tx=tx=-tx=¡Ä

1/k=-1/k=1/k=-1/k=¡Ä
1/k=i(1/k)=(-1/k)=i(-1/k)=1/k=i(1/k)=(-1/k)=¡Ä
k=ik=-k=i(-k)=k=ik=-k=i(-k)=k=¡Ä
k=tx=1
tx=itx=-tx=i(-tx)=tx=itx=-tx=i(-tx)=tx=¡Ä

¦¤E¦¤t=¦¤p¦¤x=h/4¦Ð
¦¤E¦¤t=h/4¦Ð
¦¤E=F¦¤x
F¦¤x¦¤t=h/4¦Ð
F(¦¤x/¦¤t)¦¤t¦¤t=h/4¦Ð
v=¦¤x/¦¤t
Fv¦¤t¦¤t=h/4¦Ð
¦¤t=C=1
Fv=1
v=x
Fx=1
F=1/x
Fv=1
F=1/v
F=1/x
F=1/v=1/x
1/v=t
F=1/v=1/x=t
F=t
v=x
tx=-tx=tx=-tx=¡Ä
Fv=-Fv=Fv=-Fv=¡Ä